It takes 1 molecule of nitrogen and 3

Question

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

2N2 and 6H2
2 n sub 2 and 6 h sub 2

4N2 and 4H2
4 n sub 2 and 4 h sub 2

8N2 and 4H2
8 n sub 2 and 4 h sub 2

5N2 and 6H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we can use the stoichiometry of the reaction:

\[ 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \]

From this equation, we see that:

• 1 molecule of nitrogen (\( \text{N}_2 \)) reacts with 3 molecules of hydrogen (\( \text{H}_2 \)) to produce 2 molecules of ammonia (\( \text{NH}_3 \)).
• Therefore, the ratio needed for the reaction is 1:3 for nitrogen and hydrogen.

Let’s analyze each of the provided options:

1. 2N2 and 6H2:

   • \(2 \text{N}_2\) will require \(2 \times 3 = 6 \text{H}_2\)
   • This combination will produce \(2 \times 2 = 4 \text{NH}_3\) (no leftovers)

2. 4N2 and 4H2:

   • \(4 \text{N}_2\) will require \(4 \times 3 = 12 \text{H}_2\)
   • This combination will not use all the available \( \text{H}_2\) (leftovers)

3. 8N2 and 4H2:

   • \(8 \text{N}_2\) will require \(8 \times 3 = 24 \text{H}_2\)
   • This combination has insufficient \( \text{H}_2\) (leftovers)

4. 5N2 and 6H2:

   • \(5 \text{N}_2\) will require \(5 \times 3 = 15 \text{H}_2\)
   • This combination has insufficient \( \text{H}_2\) (leftovers)

Based on the analysis, the only combination that produces ammonia with no leftovers is:

2N2 and 6H2.