To begin a football game, the kicker has to kick off. The football follows the path h(x) = −130x(x−60)

, where h(x)
is the height of the football and x is the horizontal distance it has traveled in yards.

Answer the questions below:

(1 point)
1) What is the y-intercept? Write your answer as an ordered pair.

2) At what time is the football at the highest height?
seconds.

3) The ball will have traveled
yards before hitting the ground.

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 month ago

To analyze the path of the football described by the function \( h(x) = -130x(x - 60) \), we will work through the questions one by one.

1) **What is the y-intercept? Write your answer as an ordered pair.**

The y-intercept occurs when \( x = 0 \).

\[
h(0) = -130(0)(0 - 60) = 0
\]

Therefore, the y-intercept is \( (0, 0) \).

2) **At what time is the football at the highest height?**

The function \( h(x) \) is a quadratic equation which opens downwards ( since the coefficient of \( x^2 \) is negative), meaning it has a maximum point (the vertex). The x-coordinate of the vertex of a quadratic function of the form \( ax^2 + bx + c \) is given by the formula:

\[
x = -\frac{b}{2a}
\]

For the function \( h(x) = -130x^2 + 7800x \):
- \( a = -130 \)
- \( b = 7800 \)

Thus,

\[
x = -\frac{7800}{2(-130)} = \frac{7800}{260} = 30
\]

Therefore, the football reaches its highest height at \( x = 30 \) yards.

3) **The ball will have traveled \_\_\_\_ yards before hitting the ground.**

The football will hit the ground when \( h(x) = 0 \). We can solve for \( x \) when \( h(x) \) equals zero:

\[
h(x) = -130x(x - 60) = 0
\]

Setting each factor to zero gives:

\[
-130x = 0 \quad \Rightarrow \quad x = 0
\]
\[
x - 60 = 0 \quad \Rightarrow \quad x = 60
\]

Therefore, the ball will hit the ground after traveling \( 60 \) yards.

To summarize the answers:
1) The y-intercept is: \( (0, 0) \)
2) The football reaches its highest height at: \( 30 \) yards
3) The ball will have traveled: \( 60 \) yards before hitting the ground.