A voltage difference of V = Q/C = 14*10^-9/28*10^-12 = 500 V will appear between the spheres after the transfer is made.
The electrical energy of the charged spheres is (1/2) C V^2
You don't need to know or use the separation distance.
It's a pretty low number: microjoules
Two uncharged metal spheres, spaced 20.0 cm apart, have a capacitance of 28.0 pF.
How much work would it take to move 14.0 nC of charge from one sphere to the other?
*Please report answer in Joules.
1 answer
2 answers