The reaction: 2 HI== H2 + I2, is second order and the rate constant at 800 K is 9.70 x 10-2 M-1 s-1. How long will it take for 8.00 x 10-2 mol/L of HI to decrease to one-fourth of its initial concentration?

Question

The reaction: 2 HI==> H2 + I2, is second order and the rate constant at 800 K is 9.70 x 10-2 M-1 s-1. How long will it take for 8.00 x 10-2 mol/L of HI to decrease to one-fourth of its initial concentration?

DrBob222 · Answer

(1/A) - (1/Ao) = akt Just make up a number for Ao, then put in 1/4 of that number for A..