The expression you provided is \(\frac{(4^{-2})^{-1}}{4^{-1}}\).
Let's simplify it step by step.
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Simplify \((4^{-2})^{-1}\): \[ (4^{-2})^{-1} = 4^{2} = 16 \]
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Simplify the denominator \(4^{-1}\): \[ 4^{-1} = \frac{1}{4} \]
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Now substitute back into the expression: \[ \frac{16}{4} \]
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Finally simplify \(\frac{16}{4}\): \[ \frac{16}{4} = 4 \]
So the expression simplifies to \(4\).
Therefore, the correct answer is: \[ \boxed{4} \]