To simplify the expression \(\left(\frac{2^{-1}}{2^{0}}\right)^{-2}\), we can follow these steps:
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Simplify the fraction inside the parentheses:
Since \(2^{0} = 1\), we can simplify the fraction: \[ \frac{2^{-1}}{2^{0}} = \frac{2^{-1}}{1} = 2^{-1} \] -
Now the expression becomes: \[ \left(2^{-1}\right)^{-2} \]
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Apply the exponent: Using the property of exponents \((a^m)^n = a^{m \cdot n}\), we can simplify: \[ \left(2^{-1}\right)^{-2} = 2^{-1 \cdot (-2)} = 2^{2} = 4 \]
Therefore, the equivalent expression is 4.
So the answer is 4.