Question
H2Se+H2O→SeH−+H3O+
identify the acid, base, conjugate acid, and conjugate base in this reaction.
identify the acid, base, conjugate acid, and conjugate base in this reaction.
Answers
GPT-4o mini
In the reaction:
\[
\text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+
\]
we can identify the acid, base, conjugate acid, and conjugate base as follows:
1. **Acid**: \(\text{H}_2\text{Se}\) (dihydrogen selenide) is acting as the acid because it donates a proton (H⁺).
2. **Base**: \(\text{H}_2\text{O}\) (water) is acting as the base because it accepts a proton (H⁺) to form the hydronium ion.
3. **Conjugate Acid**: \(\text{H}_3\text{O}^+\) (hydronium ion) is the conjugate acid of water. It is formed when water accepts a proton.
4. **Conjugate Base**: \(\text{SeH}^-\) (selenide ion) is the conjugate base of \(\text{H}_2\text{Se}\). It is formed when \(\text{H}_2\text{Se}\) donates a proton.
So, to summarize:
- Acid: \(\text{H}_2\text{Se}\)
- Base: \(\text{H}_2\text{O}\)
- Conjugate Acid: \(\text{H}_3\text{O}^+\)
- Conjugate Base: \(\text{SeH}^-\)
\[
\text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+
\]
we can identify the acid, base, conjugate acid, and conjugate base as follows:
1. **Acid**: \(\text{H}_2\text{Se}\) (dihydrogen selenide) is acting as the acid because it donates a proton (H⁺).
2. **Base**: \(\text{H}_2\text{O}\) (water) is acting as the base because it accepts a proton (H⁺) to form the hydronium ion.
3. **Conjugate Acid**: \(\text{H}_3\text{O}^+\) (hydronium ion) is the conjugate acid of water. It is formed when water accepts a proton.
4. **Conjugate Base**: \(\text{SeH}^-\) (selenide ion) is the conjugate base of \(\text{H}_2\text{Se}\). It is formed when \(\text{H}_2\text{Se}\) donates a proton.
So, to summarize:
- Acid: \(\text{H}_2\text{Se}\)
- Base: \(\text{H}_2\text{O}\)
- Conjugate Acid: \(\text{H}_3\text{O}^+\)
- Conjugate Base: \(\text{SeH}^-\)