To simplify the given expression \(\frac{2^2}{2^{-7}} \times 2\), we can start by simplifying the fraction:
- Simplifying the Fraction: When we divide powers with the same base, we subtract the exponents. So,
\[ \frac{2^2}{2^{-7}} = 2^{2 - (-7)} = 2^{2 + 7} = 2^9. \]
- Multiplying by \(2\): Now, we multiply \(2^9\) by \(2\). We can write \(2\) as \(2^1\):
\[ 2^9 \times 2^1 = 2^{9 + 1} = 2^{10}. \]
Therefore, the expression simplifies to \(2^{10}\).
So the answer is \(2^{10}\).
Correct Answer: \(2, \text{ to the power } 10\).