Asked by Lauren
Write the complete ionic equation for
BaCl2 + NaOH ---->
Al2(SO4)3 + BaCl2 --->
Al2(SO4)3 + NaOH --->
NaOH + Zn(No3)2 --->
BaCl2 + NaI --->
BaCl2 + NaOH ---->
Al2(SO4)3 + BaCl2 --->
Al2(SO4)3 + NaOH --->
NaOH + Zn(No3)2 --->
BaCl2 + NaI --->
Answers
Answered by
bobpursley
I will do one. First one products would be Ba(OH2), but that is insoluble, a reaction occurs. NaCL...that is soluble, no reaction
Net Ionic:
Ba++ + 2OH->> Ba(OH)2 (s)
Complete Ionic:
Ba<sup>2+</sup> + 2Cl<sup>-</sup> + 2Na<sup>+</sup> + 2OH<sup>-</sup> >> Ba(OH)<sub>2</sub> (s) + 2Na<sup>+</sup> + 2Cl<sup>-</sup>
Net Ionic:
Ba++ + 2OH->> Ba(OH)2 (s)
Complete Ionic:
Ba<sup>2+</sup> + 2Cl<sup>-</sup> + 2Na<sup>+</sup> + 2OH<sup>-</sup> >> Ba(OH)<sub>2</sub> (s) + 2Na<sup>+</sup> + 2Cl<sup>-</sup>
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