Question
Solve the following linear equation
6y+17-6y=17
Y=
6y+17-6y=17
Y=
Answers
Answer
That’s not correct what does y=
Answered by
GPT-4o mini
To solve the equation \( 6y + 17 - 6y = 17 \), we can first simplify it.
Notice that \( 6y \) and \( -6y \) cancel each other out:
\[
6y - 6y + 17 = 17
\]
This simplifies to:
\[
17 = 17
\]
This statement is always true, which means that the equation does not depend on \( y \). Therefore, \( y \) can be any real number.
In conclusion, the solution to the equation is:
\[
y = \text{any real number}
\]
Notice that \( 6y \) and \( -6y \) cancel each other out:
\[
6y - 6y + 17 = 17
\]
This simplifies to:
\[
17 = 17
\]
This statement is always true, which means that the equation does not depend on \( y \). Therefore, \( y \) can be any real number.
In conclusion, the solution to the equation is:
\[
y = \text{any real number}
\]
Answered by
GPT-4o mini
I understand the confusion. Let's clarify this situation.
The equation you provided is:
\[
6y + 17 - 6y = 17
\]
As we simplified it, we noticed that:
\[
6y - 6y + 17 = 17
\]
This simplifies to:
\[
17 = 17
\]
Since this is a true statement and does not involve \( y \) at all, it indicates that the equation is valid for all values of \( y \).
Thus, we cannot determine a unique value for \( y \). The equation is an identity, meaning:
\[
y \text{ can be any real number}
\]
If you're asking for a specific solution in a certain context, please provide more details!
The equation you provided is:
\[
6y + 17 - 6y = 17
\]
As we simplified it, we noticed that:
\[
6y - 6y + 17 = 17
\]
This simplifies to:
\[
17 = 17
\]
Since this is a true statement and does not involve \( y \) at all, it indicates that the equation is valid for all values of \( y \).
Thus, we cannot determine a unique value for \( y \). The equation is an identity, meaning:
\[
y \text{ can be any real number}
\]
If you're asking for a specific solution in a certain context, please provide more details!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.