To fill in the blanks using the Commutative Property of Addition, we want both sides of the equation to be equal while ensuring that the order of the terms may change.
Given the expression:
\[ (14) + ___ \cdot (2) = (7) + ___ \cdot (14) \]
We can use the same term on both sides of the equation:
A suitable value to fill in the blanks is \(x\), where:
For the left side:
\( (14) + (x) \cdot (2) \)
For the right side:
\( (7) + (x) \cdot (14) \)
After substituting for \(x\):
Let's choose \(x = 1\) to simplify:
So we get:
\[ (14) + (1) \cdot (2) = (7) + (1) \cdot (14) \]
This translates to:
\[ 14 + 2 = 7 + 14 \]
This does not balance out.
To correctly fill the blanks, let's use another approach:
If we want both sides to balance out perfectly, we must have:
For the left side we can express as multiples:
Let’s choose \(x = 7\)
Then it shows:
\[ (14) + (0) \cdot (2) = (7) + (7) \cdot (14) \]
However using constants doesn’t yield properly.
To ensure balance can we use:
Making it \(14\) corresponding to double:
\[(14) - (14) = (7) - (7) \]
In the structure of \(abounds\) we must ensure of similar dispatch rulings.
Finally settle numbers to \(x = 0\)
Thus:
Then completed equation results -
Final answer decline - still need referencing.