Asked by Kelly
Reacting 959 mol of SiO2 with excess carbon yields 28.8 kg of SiC. What is the percentage yield?
SiO2 + 3C--> SiC + 2 CO
SiO2 + 3C--> SiC + 2 CO
Answers
Answered by
DrBob222
You must determine first the theoretical yield.
Using the coefficients in the balanced equation, convert moles SiO2 to moles SiC.
Convert moles SiC to grams. g = moles x molar mass. This is the theoretical yield.
%yield = [actual yield/theoretical yield]*100 = ??
actual yield is given in the problem as 28.8 kg but you must change this to grams OR change the theoretical yield to kg.
Using the coefficients in the balanced equation, convert moles SiO2 to moles SiC.
Convert moles SiC to grams. g = moles x molar mass. This is the theoretical yield.
%yield = [actual yield/theoretical yield]*100 = ??
actual yield is given in the problem as 28.8 kg but you must change this to grams OR change the theoretical yield to kg.
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