To write the equation of the line in slope-intercept form (y = mx + b), we first need to determine the slope (m) of the line passing through the two points (0, 2) and (1, -1).
The formula for the slope (m) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Plugging in the coordinates of the points (0, 2) and (1, -1):
\[ m = \frac{-1 - 2}{1 - 0} = \frac{-3}{1} = -3 \]
Now that we have the slope, we can use one of the points to find the y-intercept (b). Since the point (0, 2) is on the y-axis, the y-intercept is simply:
\[ b = 2 \]
Now we can write the equation of the line in slope-intercept form:
\[ y = mx + b \]
Substituting the values of m and b we found:
\[ y = -3x + 2 \]
Thus, the equation of the line in slope-intercept form is:
\[ \boxed{y = -3x + 2} \]
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