Asked by Saira
Calculate the pH of a 0.10 M solution of barium hydroxide, Ba(OH)2.
Answers
Answered by
DrBob222
Ba(OH)2 ==> Ba^ + 2OH^-
So 0.1 M Ba(OH)2 gives you twice that for OH^- in solution or (OH^-) = 0.2 M.
pOH = ??, then pH = 14-pOH.
So 0.1 M Ba(OH)2 gives you twice that for OH^- in solution or (OH^-) = 0.2 M.
pOH = ??, then pH = 14-pOH.
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