To solve the quadratic equation \( x^2 - 22x + 1 = 15 \) by completing the square, follow these steps:
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Rearrange the equation: \[ x^2 - 22x + 1 - 15 = 0 \] This simplifies to: \[ x^2 - 22x - 14 = 0 \]
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Move the constant to the other side: \[ x^2 - 22x = 14 \]
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Complete the square:
- Take half of the coefficient of \( x \) (which is -22), square it, and add it to both sides. Half of -22 is -11, and squaring it gives \( 121 \).
- So, add \( 121 \) to both sides: \[ x^2 - 22x + 121 = 14 + 121 \] This simplifies to: \[ (x - 11)^2 = 135 \]
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Take the square root of both sides: \[ x - 11 = \pm \sqrt{135} \]
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Solve for \( x \): \[ x = 11 \pm \sqrt{135} \]
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Simplify \( \sqrt{135} \): \[ \sqrt{135} = \sqrt{9 \cdot 15} = 3\sqrt{15} \] Thus, we can write: \[ x = 11 \pm 3\sqrt{15} \]
So, the final solutions are: \[ x = 11 + 3\sqrt{15}, \quad x = 11 - 3\sqrt{15} \]
The correct response from your options is: \[ x = 11 + 3\sqrt{15}, \quad 11 - 3\sqrt{15} \]