To determine if the values -1 and 73 are solutions to the equation \(3x^2 - 4x - 4 = 3\), we first need to simplify the equation.
Rearranging the equation gives us:
\[
3x^2 - 4x - 4 - 3 = 0
\]
\[
3x^2 - 4x - 7 = 0
\]
Next, we can check if -1 and 73 are solutions by substituting them into the equation.
1. For \(x = -1\):
\[
3(-1)^2 - 4(-1) - 7 = 3(1) + 4 - 7 = 3 + 4 - 7 = 0
\]
So, \(x = -1\) is a solution.
2. For \(x = 73\):
\[
3(73)^2 - 4(73) - 7 = 3(5329) - 292 - 7
\]
\[
= 15987 - 292 - 7 = 15987 - 299 = 15688 \quad (\text{not } 0)
\]
So, \(x = 73\) is not a solution.
Thus, the statement "The values -1 and 73 are both solutions to the quadratic equation \(3x^2 - 4x - 4 = 3\)" is **False**.
Now, for Question 2, since the above statement was false, the correct response would be:
"Only -1 is a solution to \(3x^2 - 4x - 4 = 3\)".
So, to summarize:
1. **False**
2. **Only -1 is a solution to \(3x^2 - 4x - 4 = 3\)**.