What is the product of the polynomials (x2y+2)(x2−y)?(1 point)

To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we will use the distributive property (also known as the FOIL method for binomials).

Let's compute:

\[
(x^2y + 2)(x^2 - y) = x^2y \cdot x^2 + x^2y \cdot (-y) + 2 \cdot x^2 + 2 \cdot (-y)
\]

Now, let's calculate each term:

1. \(x^2y \cdot x^2 = x^{4}y\)
2. \(x^2y \cdot (-y) = -x^2y^2\)
3. \(2 \cdot x^2 = 2x^2\)
4. \(2 \cdot (-y) = -2y\)

Now, combining all these terms together:

\[
x^{4}y - x^{2}y^{2} + 2x^{2} - 2y
\]

Thus, the product of the polynomials \((x^2y + 2)(x^2 - y)\) is:

\[
\boxed{x^{4}y - x^{2}y^{2} + 2x^{2} - 2y}
\]