Question

Two people are on a train that is moving at 10:00 a.m. s North they are walking one Ms cell relative to the train relative to the ground or motion is 9 Ms North

Answer 1

To analyze the scenario, let’s clarify the movements of the two people on the train.

1. The train is moving north at a speed of 10 m/s.
2. Each person is walking inside the train at a speed of 1 m/s relative to the train.

Now, let's determine their speed relative to the ground:

- If the people are walking in the same direction as the train (north), we add their speed to the train's speed:

\[
\text{Speed relative to ground} = \text{Train speed} + \text{Walking speed} = 10 \text{ m/s} + 1 \text{ m/s} = 11 \text{ m/s (North)}
\]

- If the people are walking in the opposite direction (south), we subtract their speed from the train's speed:

\[
\text{Speed relative to ground} = \text{Train speed} - \text{Walking speed} = 10 \text{ m/s} - 1 \text{ m/s} = 9 \text{ m/s (North)}
\]

In your statement, you mentioned that their motion is 9 m/s North. This would imply that they are walking in the opposite direction of the train's motion (south).

To summarize:
- Walking north (same direction as the train): 11 m/s North relative to the ground.
- Walking south (opposite direction to the train): 9 m/s North relative to the ground.

Please let me know if you need further clarification!