To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials).
1. Distributing \(x^2y\) to each term in \((x^2 - y)\):
\[
x^2y \cdot x^2 = x^4y
\]
\[
x^2y \cdot (-y) = -x^2y^2
\]
2. Distributing \(2\) to each term in \((x^2 - y)\):
\[
2 \cdot x^2 = 2x^2
\]
\[
2 \cdot (-y) = -2y
\]
Now, we can combine these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of \((x^2y + 2)(x^2 - y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
From the responses provided, the correct answer is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So the final answer is:
**x^4y - x^2y^2 + 2x^2 - 2y**