Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A movie theater offers two options for membership. The first option costs $15 per ticket but an initial fee of $10. The second...Question
A movie theater offers two options for membership. The first option costs $15 per ticket but an initial fee of $5. The second option costs $12.50 per ticket but an initial fee of $50 . After how many tickets are both options the same price?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find out after how many tickets the two membership options cost the same, we can set up an equation for each option.
Let \( x \) be the number of tickets.
**Option 1**: Costs \( 5 + 15x \) (initial fee of $5 plus $15 for each ticket)
**Option 2**: Costs \( 50 + 12.50x \) (initial fee of $50 plus $12.50 for each ticket)
We want to find \( x \) such that the costs for both options are equal:
\[
5 + 15x = 50 + 12.50x
\]
Now, let's solve for \( x \):
1. Subtract \( 12.50x \) from both sides:
\[
5 + 15x - 12.50x = 50
\]
This simplifies to:
\[
5 + 2.5x = 50
\]
2. Subtract 5 from both sides:
\[
2.5x = 45
\]
3. Divide both sides by 2.5:
\[
x = \frac{45}{2.5} = 18
\]
Thus, the two membership options cost the same after \( \boxed{18} \) tickets.
Let \( x \) be the number of tickets.
**Option 1**: Costs \( 5 + 15x \) (initial fee of $5 plus $15 for each ticket)
**Option 2**: Costs \( 50 + 12.50x \) (initial fee of $50 plus $12.50 for each ticket)
We want to find \( x \) such that the costs for both options are equal:
\[
5 + 15x = 50 + 12.50x
\]
Now, let's solve for \( x \):
1. Subtract \( 12.50x \) from both sides:
\[
5 + 15x - 12.50x = 50
\]
This simplifies to:
\[
5 + 2.5x = 50
\]
2. Subtract 5 from both sides:
\[
2.5x = 45
\]
3. Divide both sides by 2.5:
\[
x = \frac{45}{2.5} = 18
\]
Thus, the two membership options cost the same after \( \boxed{18} \) tickets.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.