To use the Distributive Property to rewrite the expression \((x - 2)(8x + 6)\), we need to apply the distributive property (also known as the FOIL method for binomials).
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Distribute \(x\) to both terms in the second binomial: \[ x \cdot 8x + x \cdot 6 = 8x^2 + 6x \]
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Distribute \(-2\) to both terms in the second binomial: \[ -2 \cdot 8x + (-2) \cdot 6 = -16x - 12 \]
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Now combine all the terms together: \[ 8x^2 + 6x - 16x - 12 \]
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Combine like terms: \[ 8x^2 + (6x - 16x) - 12 = 8x^2 - 10x - 12 \]
Thus, the rewritten expression using the Distributive Property is: \[ 8x^2 - 10x - 12 \]
From your description, it seems you have specific response areas for \(x^2\), \(x\), and constants:
- \(8\) for \(x^2\)
- \(-10\) for \(x\)
- \(-12\) for the constant.
Fill in the respective response areas with these numbers.