Asked by i love miners
What type of number is 12/3
A.
whole number
B.
integer
C.
rational
D.
irrational
A.
whole number
B.
integer
C.
rational
D.
irrational
Answers
Answered by
GPT-4o mini
The number \( \frac{12}{3} \) simplifies to \( 4 \).
- A whole number is a positive integer or zero, so 4 is a whole number.
- An integer includes both positive and negative whole numbers and zero, so 4 is an integer.
- A rational number is any number that can be expressed as the quotient of two integers, so \( \frac{12}{3} \) is a rational number.
- An irrational number is a number that cannot be expressed as a fraction of two integers.
Given the options, the correct answers would be:
A. whole number
B. integer
C. rational
So, \( \frac{12}{3} \) is a whole number, an integer, and a rational number.
- A whole number is a positive integer or zero, so 4 is a whole number.
- An integer includes both positive and negative whole numbers and zero, so 4 is an integer.
- A rational number is any number that can be expressed as the quotient of two integers, so \( \frac{12}{3} \) is a rational number.
- An irrational number is a number that cannot be expressed as a fraction of two integers.
Given the options, the correct answers would be:
A. whole number
B. integer
C. rational
So, \( \frac{12}{3} \) is a whole number, an integer, and a rational number.
Answered by
i love miners
sovle √64
Answered by
GPT-4o mini
The square root of \( 64 \) is \( 8 \), since \( 8 \times 8 = 64 \). So, \( \sqrt{64} = 8 \).
Answered by
i love miners
√27is between which two whole numbers on the number line?
A.
3 and 4
B.
4 and 5
C.
5 and 6
D.
6 and 7
A.
3 and 4
B.
4 and 5
C.
5 and 6
D.
6 and 7
Answered by
GPT-4o mini
To determine between which two whole numbers \( \sqrt{27} \) falls, we can find the squares of the whole numbers around it.
- \( 3^2 = 9 \)
- \( 4^2 = 16 \)
- \( 5^2 = 25 \)
- \( 6^2 = 36 \)
Since \( 27 \) is between \( 25 \) (which is \( 5^2 \)) and \( 36 \) (which is \( 6^2 \)), it follows that:
\[
5 < \sqrt{27} < 6
\]
Thus, \( \sqrt{27} \) is between **5 and 6**.
The correct answer is:
**C. 5 and 6**.
- \( 3^2 = 9 \)
- \( 4^2 = 16 \)
- \( 5^2 = 25 \)
- \( 6^2 = 36 \)
Since \( 27 \) is between \( 25 \) (which is \( 5^2 \)) and \( 36 \) (which is \( 6^2 \)), it follows that:
\[
5 < \sqrt{27} < 6
\]
Thus, \( \sqrt{27} \) is between **5 and 6**.
The correct answer is:
**C. 5 and 6**.
Answered by
i love miners
solve √64/121 A.
64/121
B.
8/11
C.
4/11
D.
32/
64/121
B.
8/11
C.
4/11
D.
32/
Answered by
GPT-4o mini
To solve \( \sqrt{\frac{64}{121}} \), we can use the property of square roots that states:
\[
\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}
\]
Applying this property:
\[
\sqrt{\frac{64}{121}} = \frac{\sqrt{64}}{\sqrt{121}}
\]
We know that:
\[
\sqrt{64} = 8 \quad \text{and} \quad \sqrt{121} = 11
\]
Thus:
\[
\sqrt{\frac{64}{121}} = \frac{8}{11}
\]
So the answer is:
**B. \( \frac{8}{11} \)**.
\[
\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}
\]
Applying this property:
\[
\sqrt{\frac{64}{121}} = \frac{\sqrt{64}}{\sqrt{121}}
\]
We know that:
\[
\sqrt{64} = 8 \quad \text{and} \quad \sqrt{121} = 11
\]
Thus:
\[
\sqrt{\frac{64}{121}} = \frac{8}{11}
\]
So the answer is:
**B. \( \frac{8}{11} \)**.
Answered by
i love miners
Is the following number rational or irrational?
.0692
A.
rational
B.
irrational
.0692
A.
rational
B.
irrational
Answered by
GPT-4o mini
The number \( 0.0692 \) can be expressed as a fraction. For example, it can be written as \( \frac{692}{10000} \). Since it can be represented as the quotient of two integers, it is classified as a rational number.
Thus, the correct answer is:
**A. rational**.
Thus, the correct answer is:
**A. rational**.