What type of number is 12/3

A.
whole number

B.
integer

C.
rational

D.
irrational

9 answers

The number \( \frac{12}{3} \) simplifies to \( 4 \).

  • A whole number is a positive integer or zero, so 4 is a whole number.
  • An integer includes both positive and negative whole numbers and zero, so 4 is an integer.
  • A rational number is any number that can be expressed as the quotient of two integers, so \( \frac{12}{3} \) is a rational number.
  • An irrational number is a number that cannot be expressed as a fraction of two integers.

Given the options, the correct answers would be:

A. whole number
B. integer
C. rational

So, \( \frac{12}{3} \) is a whole number, an integer, and a rational number.

sovle √64

The square root of \( 64 \) is \( 8 \), since \( 8 \times 8 = 64 \). So, \( \sqrt{64} = 8 \).

√27is between which two whole numbers on the number line?

A.
3 and 4

B.
4 and 5

C.
5 and 6

D.
6 and 7

To determine between which two whole numbers \( \sqrt{27} \) falls, we can find the squares of the whole numbers around it.

  • \( 3^2 = 9 \)
  • \( 4^2 = 16 \)
  • \( 5^2 = 25 \)
  • \( 6^2 = 36 \)

Since \( 27 \) is between \( 25 \) (which is \( 5^2 \)) and \( 36 \) (which is \( 6^2 \)), it follows that:

\[ 5 < \sqrt{27} < 6 \]

Thus, \( \sqrt{27} \) is between 5 and 6.

The correct answer is:

C. 5 and 6.

solve √64/121 A.
64/121

B.
8/11

C.
4/11

D.
32/

To solve \( \sqrt{\frac{64}{121}} \), we can use the property of square roots that states:

\[ \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \]

Applying this property:

\[ \sqrt{\frac{64}{121}} = \frac{\sqrt{64}}{\sqrt{121}} \]

We know that:

\[ \sqrt{64} = 8 \quad \text{and} \quad \sqrt{121} = 11 \]

Thus:

\[ \sqrt{\frac{64}{121}} = \frac{8}{11} \]

So the answer is:

B. \( \frac{8}{11} \).

Is the following number rational or irrational?
.0692

A.
rational

B.
irrational

The number \( 0.0692 \) can be expressed as a fraction. For example, it can be written as \( \frac{692}{10000} \). Since it can be represented as the quotient of two integers, it is classified as a rational number.

Thus, the correct answer is:

A. rational.

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