Write y−2=32(x+2) in slope-intercept form.(1 point)

To rewrite the equation \( y - 2 = 32(x + 2) \) in slope-intercept form, we need to isolate \( y \).

1. Start with the given equation:
\[
y - 2 = 32(x + 2)
\]

2. Distribute the \( 32 \) on the right side:
\[
y - 2 = 32x + 64
\]

3. Now, add \( 2 \) to both sides to solve for \( y \):
\[
y = 32x + 64 + 2
\]
\[
y = 32x + 66
\]

Now, we have the equation in slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

However, none of your answer options match our result \( y = 32x + 66 \). If you have options of answers that only include certain values, there could be an error or miscommunication in the values given.

Based on the options provided:
- \( y = 32x + 5 \)
- \( y = 32 + 5x \)
- \( y = 32x + 6 \)
- \( y = 32x + 32 \)

None of these are correct based on the equation derived. The correct result is:
\[
y = 32x + 66
\]