Find the product of the polynomials (9x2−6x+1)(3x−1) .(1 point) Responses 27x3+27x2+9x+1 27 x cubed plus 27 x squared plus 9 x plus 1 27x3−27x2+9x−1 27 x cubed minus 27 x squared plus 9 x minus 1 27x3−27x4+9x−1 27 x cubed minus 27 x superscript 4 baseline plus 9 x minus 1 27x3−9x2+27x−1

To find the product of the polynomials \( (9x^2 - 6x + 1)(3x - 1) \), we can apply the distributive property (also known as the FOIL method for binomials).

1. Multiply \( 9x^2 \) by each term in \( (3x - 1) \):
\[
9x^2 \cdot 3x = 27x^3
\]
\[
9x^2 \cdot (-1) = -9x^2
\]

2. Multiply \( -6x \) by each term in \( (3x - 1) \):
\[
-6x \cdot 3x = -18x^2
\]
\[
-6x \cdot (-1) = 6x
\]

3. Multiply \( 1 \) by each term in \( (3x - 1) \):
\[
1 \cdot 3x = 3x
\]
\[
1 \cdot (-1) = -1
\]

Now, combine all these results:
\[
27x^3 + (-9x^2 - 18x^2) + (6x + 3x) + (-1)
\]
Combine the like terms:
\[
27x^3 + (-27x^2) + 9x - 1
\]

This simplifies to:
\[
27x^3 - 27x^2 + 9x - 1
\]

Thus, the product of the polynomials is:
\[
\boxed{27x^3 - 27x^2 + 9x - 1}
\]