Write the linear equation 3y = 6x - 18 in slope-intercept form.

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1 answer

To write the equation \(3y = 6x - 18\) in slope-intercept form, we need to solve for \(y\). The slope-intercept form of a linear equation is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Starting with the original equation:

\[ 3y = 6x - 18 \]

We will divide each term by 3 to isolate \(y\):

\[ y = \frac{6x}{3} - \frac{18}{3} \]

This simplifies to:

\[ y = 2x - 6 \]

Thus, the equation in slope-intercept form is:

\[ y = 2x - 6 \]

In this equation, the slope \(m\) is 2, and the y-intercept \(b\) is -6.