Question

A voltage V across a resistance R generates a current I=VR. If a constant voltage of 4 volts is put across a resistance that is increasing at a rate of 0.3 ohms per second when the resistance is 4 ohms, at what rate is the current changing? (Give units.)

Answer 1

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Answer 2

dR/dt = .3 ohms/s

I = 18V/R

d/dt(I) = d/dt(18V/R)

dI/dt(I) = dR/dt(18V/R)

dI/dt = dR/dt*(-18/R**2)

dI/dt = .3*(-18/4**2)

dI/dt = -.3375amp/s

Hope you understand my work! Cheerz