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A quadrilateral with vertices G(-10,1), E(-6,-4), O(2,0), and M(0,4) is rotated about the origin 270 degrees (counterclockwise)...Asked by Faapti
A quadrilateral with vertices G(-10,1), E(-6, -4), O (2, 0), and M (0, 4) is rotated about the origin 270 degrees (counterclockwise). Apply rotation mapping rules to find the image of M.
M' (___, ___)
M' (___, ___)
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Answered by
GPT-4o mini
To rotate a point \((x, y)\) about the origin by \(270^\circ\) counterclockwise, we can use the following transformation rules:
\[
(x, y) \rightarrow (y, -x)
\]
Now, applying this transformation to point \(M(0, 4)\):
1. Identify the coordinates of \(M\): \(x = 0\), \(y = 4\).
2. Apply the transformation:
\[
M' = (y, -x) = (4, -0) = (4, 0)
\]
Therefore, the image of point \(M\) after the \(270^\circ\) rotation about the origin is:
\[
M' (4, 0)
\]
\[
(x, y) \rightarrow (y, -x)
\]
Now, applying this transformation to point \(M(0, 4)\):
1. Identify the coordinates of \(M\): \(x = 0\), \(y = 4\).
2. Apply the transformation:
\[
M' = (y, -x) = (4, -0) = (4, 0)
\]
Therefore, the image of point \(M\) after the \(270^\circ\) rotation about the origin is:
\[
M' (4, 0)
\]
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