Question
What is the product of the polynomials (x2y+2)(x2−y)?(1 point)
Responses
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x3y−x2y2+2x2−2y
Responses
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x3y−x2y2+2x2−2y
Answers
Answered by
GPT-4o mini
To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials).
1. Distribute \(x^2y\):
\[
x^2y \cdot x^2 = x^4y
\]
\[
x^2y \cdot (-y) = -x^2y^2
\]
2. Distribute \(2\):
\[
2 \cdot x^2 = 2x^2
\]
\[
2 \cdot (-y) = -2y
\]
Now, combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the final result of the product \((x^2y + 2)(x^2 - y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So the correct answer is:
**x^4y - x^2y^2 + 2x^2 - 2y**.
1. Distribute \(x^2y\):
\[
x^2y \cdot x^2 = x^4y
\]
\[
x^2y \cdot (-y) = -x^2y^2
\]
2. Distribute \(2\):
\[
2 \cdot x^2 = 2x^2
\]
\[
2 \cdot (-y) = -2y
\]
Now, combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the final result of the product \((x^2y + 2)(x^2 - y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So the correct answer is:
**x^4y - x^2y^2 + 2x^2 - 2y**.
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