Question

A toy race car zooms across the ground with an acceleration of 1.8 m/s^2. After 3 seconds it has a final velocity of 12.2 m/s, what is the toy car's initial velocity? a= (Vf-Vi)/t (1 point) Responses 22.8 m/s 22.8 m/s 6.8 m/s 6.8 m/s 9.8 m/s 9.8 m/s 1.8 m/s

Answer 1

To find the toy car's initial velocity (Vi), you can use the formula for acceleration:

\[
a = \frac{Vf - Vi}{t}
\]

In this case, you've been given:

- \( a = 1.8 \, \text{m/s}^2 \)
- \( Vf = 12.2 \, \text{m/s} \)
- \( t = 3 \, \text{s} \)

Rearranging the formula to solve for \( Vi \):

\[
Vi = Vf - a \cdot t
\]

Now plug in the values:

\[
Vi = 12.2 \, \text{m/s} - (1.8 \, \text{m/s}^2 \cdot 3 \, \text{s})
\]

Calculating the term \( 1.8 \cdot 3 \):

\[
1.8 \cdot 3 = 5.4 \, \text{m/s}
\]

Now substitute it back into the equation:

\[
Vi = 12.2 \, \text{m/s} - 5.4 \, \text{m/s}
\]

Calculating \( Vi \):

\[
Vi = 6.8 \, \text{m/s}
\]

So the toy car's initial velocity is **6.8 m/s**.