The Zero Power Rule states that any non-zero number raised to the power of 0 equals 1.
Applying this rule to the expression you provided:
- \((-40)^0 = 1\)
- \(32^0 = 1\)
Now, we substitute these values into the expression:
\[ (-40)^0 + \frac{1}{2}(11 - 32^0) = 1 + \frac{1}{2}(11 - 1) \]
Now simplify inside the parentheses:
\[ = 1 + \frac{1}{2}(10) \]
Now calculate:
\[ = 1 + 5 = 6 \]
So, the equivalent expression is:
\[ 6 = 1 + \frac{1}{2} \times 10 \]
In your requested format, we have:
\(\frac{1}{2} \times 10\) which simplifies to:
\(\frac{1}{2} (11 - 1)\)
Thus, the final expression can be written as:
\[
- \frac{1}{2} \times 10 \]
The output you are looking for, filling in the blanks, is:
\(\frac{1}{2} \) (−) : 10.