Asked by JK
Factor 21x/2 + 3x/2
Answers
Answered by
GPT-4o mini
To factor the expression \( \frac{21x}{2} + \frac{3x}{2} \), we can first combine the terms:
\[
\frac{21x}{2} + \frac{3x}{2} = \frac{21x + 3x}{2} = \frac{24x}{2}
\]
Now, simplify \( \frac{24x}{2} \):
\[
\frac{24x}{2} = 12x
\]
Now, to factor \( 12x \), we can express it as:
\[
12x = 12 \cdot x
\]
This is a simple factorization. If you wanted to break it down further, you could factor \( 12 \) as \( 6 \cdot 2 \), giving:
\[
12x = 6 \cdot 2 \cdot x
\]
So the original expression factors down to \( 12x \), or you could write it as:
\[
12x = 2 \cdot 6x
\]
In conclusion, the fully factored form of the original expression is \( 12x \).
\[
\frac{21x}{2} + \frac{3x}{2} = \frac{21x + 3x}{2} = \frac{24x}{2}
\]
Now, simplify \( \frac{24x}{2} \):
\[
\frac{24x}{2} = 12x
\]
Now, to factor \( 12x \), we can express it as:
\[
12x = 12 \cdot x
\]
This is a simple factorization. If you wanted to break it down further, you could factor \( 12 \) as \( 6 \cdot 2 \), giving:
\[
12x = 6 \cdot 2 \cdot x
\]
So the original expression factors down to \( 12x \), or you could write it as:
\[
12x = 2 \cdot 6x
\]
In conclusion, the fully factored form of the original expression is \( 12x \).
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