Question

Solve the expression 15⋅805+4(70−6)
.(1 p

15-8^0/5 + 4 (7^0 - 6)= ?

Answer 1

so is the answer -26/5?

Answer 2

To solve the expression \( 15 \cdot 805 + 4(70 - 6) \):

1. Start by calculating \( 70 - 6 \):
\[
70 - 6 = 64
\]

2. Next, multiply \( 4 \) by \( 64 \):
\[
4 \cdot 64 = 256
\]

3. Now calculate \( 15 \cdot 805 \):
\[
15 \cdot 805 = 12075
\]

4. Finally, add the two results together:
\[
12075 + 256 = 12331
\]

So, the result of the expression \( 15 \cdot 805 + 4(70 - 6) \) is:
\[
\boxed{12331}
\]

---

Now for the second expression \( 15 - \frac{8^0}{5} + 4(7^0 - 6) \):

1. Calculate \( 8^0 \) and \( 7^0 \):
- Since any non-zero number raised to the power of zero is 1:
\[
8^0 = 1 \quad \text{and} \quad 7^0 = 1
\]

2. Substitute these values into the expression:
\[
15 - \frac{1}{5} + 4(1 - 6)
\]

3. Calculate \( 1 - 6 \):
\[
1 - 6 = -5
\]

4. Multiply by \( 4 \):
\[
4 \cdot (-5) = -20
\]

5. The expression now is:
\[
15 - \frac{1}{5} - 20
\]

6. Convert \( 15 \) to a fraction to combine:
\[
15 = \frac{75}{5}
\]

7. Now the expression is:
\[
\frac{75}{5} - \frac{1}{5} - 20
\]

8. Combine the first two terms:
\[
\frac{75 - 1}{5} = \frac{74}{5}
\]

9. Now \( 20 \) can be written as \( \frac{100}{5} \):
\[
\frac{74}{5} - \frac{100}{5} = \frac{74 - 100}{5} = \frac{-26}{5}
\]

So, the result of the expression \( 15 - \frac{8^0}{5} + 4(7^0 - 6) \) is:
\[
\boxed{-\frac{26}{5}}
\]

Answer 3

Yes, that's correct. The final answer for the expression

\[
15 - \frac{8^0}{5} + 4(7^0 - 6)
\]

is

\[
-\frac{26}{5}.
\]

This is simplified from the calculations step by step as detailed previously.