Asked by electric field
A 9500 pF capacitor holds plus and minus charges of 16.5*10-8 C. What is the voltage across the capacitor?
Answers
Answered by
kel
Q=C/V
16.5 x 10-8 / 9500 e-12
16.5 x 10-8 / 9500 e-12
Answered by
SumathiNair
A 9500 pF capacitor holds plus and minus charges of
16.5 10 C. −8
What is the voltage across
the capacitor?
16.5 10 C. −8
What is the voltage across
the capacitor?
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