Asked by electric field
                A 9500 pF capacitor holds plus and minus charges of 16.5*10-8 C. What is the voltage across the capacitor?
            
            
        Answers
                    Answered by
            kel
            
    Q=C/V
16.5 x 10-8 / 9500 e-12
    
16.5 x 10-8 / 9500 e-12
                    Answered by
            SumathiNair
            
    A 9500 pF capacitor holds plus and minus charges of 
16.5 10 C. −8
What is the voltage across
the capacitor?
    
16.5 10 C. −8
What is the voltage across
the capacitor?
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