Question

Use the table to answer the question.

x f(x)
g(x)

−2
−1
−1

−1
34
0
0 1 1
1 114
2
2 3 3
Compare the functions f(x)
and g(x)
. When is f(x)
greater than g(x)
?

(1 point)
f(x)
is greater than g(x)
when
<x<
.

Answer 1

try again the hint is
?<x<0

Answer 2

To compare the functions \( f(x) \) and \( g(x) \) based on the values provided, we can list them out as follows:

\[
\begin{array}{c|c|c}
x & f(x) & g(x) \\
\hline
-2 & -1 & -1 \\
-1 & 34 & 0 \\
0 & 1 & 1 \\
1 & 114 & 2 \\
2 & 3 & 3 \\
\end{array}
\]

Now, we can compare \( f(x) \) and \( g(x) \) at each \( x \):

- For \( x = -2 \): \( f(-2) = -1 \) and \( g(-2) = -1 \) → \( f(-2) = g(-2) \)
- For \( x = -1 \): \( f(-1) = 34 \) and \( g(-1) = 0 \) → \( f(-1) > g(-1) \)
- For \( x = 0 \): \( f(0) = 1 \) and \( g(0) = 1 \) → \( f(0) = g(0) \)
- For \( x = 1 \): \( f(1) = 114 \) and \( g(1) = 2 \) → \( f(1) > g(1) \)
- For \( x = 2 \): \( f(2) = 3 \) and \( g(2) = 3 \) → \( f(2) = g(2) \)

From the comparisons, we can conclude:

- \( f(x) > g(x) \) when \( x = -1 \) and \( x = 1 \).

In the intervals from the table, \( f(x) \) is greater than \( g(x) \) from \( x = -1 \) to \( x = 1 \).

Thus, the answer is:

**\( f(x) \) is greater than \( g(x) \) when \( -1 < x < 1 \).**