Question

5-8 raised to the power of 0 / 5 + 4(7raised to the power of 0 - 6)

Answer 1

To solve the expression \( \frac{(5-8)^0}{5} + 4(7^0 - 6) \), we'll break it down step by step.

1. **Calculate \( (5-8)^0 \)**:
\[
(5-8) = -3 \quad \text{and} \quad (-3)^0 = 1 \quad \text{(any non-zero number to the power of 0 is 1)}
\]

2. **Calculate the first term**:
\[
\frac{(5-8)^0}{5} = \frac{1}{5}
\]

3. **Calculate \( 7^0 \)**:
\[
7^0 = 1
\]

4. **Substitute back into the second term**:
\[
4(7^0 - 6) = 4(1 - 6) = 4(-5) = -20
\]

5. **Combine the two parts**:
\[
\frac{1}{5} - 20
\]

6. **Convert \(-20\) into a fraction with a denominator of 5**:
\[
-20 = \frac{-100}{5}
\]

7. **Now combine the fractions**:
\[
\frac{1}{5} - \frac{100}{5} = \frac{1 - 100}{5} = \frac{-99}{5}
\]

So, the final result is:
\[
\frac{-99}{5}
\]