Country S has 12,345,000 residents who tested positive for COVID-19. What is the largest place value of the numeric part of this quantity?

To determine the largest place value of the number 12,345,000, we first break it down by its place values:

- The digit '1' is in the ten million place.
- The digit '2' is in the million place.
- The digit '3' is in the hundred thousand place.
- The digit '4' is in the ten thousand place.
- The digit '5' is in the thousand place.
- The digit '0' is in the hundred place.
- The digit '0' is in the ten place.
- The digit '0' is in the units place.

Among these, the digit '1' in the ten million place represents the largest value.

Thus, the largest place value of the numeric part of 12,345,000 is **ten million**.

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The time it takes the population of a microorganism to reduce by half is 0.000027503 of a year. What number is the best estimation of this quantity?(1 point) Responses 0.00002 0.00002 0.03 0.03 0.00003 0.00003 0.01

To find the best estimation of \( 0.000027503 \) of a year, we can round it to a more manageable number.

- \( 0.000027503 \) is closest to \( 0.00003 \) when rounded to five decimal places.

Now, comparing with the options provided:

- \( 0.00002 \)
- \( 0.03 \)
- \( 0.00003 \)
- \( 0.01 \)

The best estimation of \( 0.000027503 \) from the given options is **0.00003**.

A total of 7,803,100 tourists visited Country A from the year 2018 to the year 2020. Round to the nearest place value, then express this number in the form of a single digit times an integer power of 10.

To express the number \( 7,803,100 \) in scientific notation, we first round it to the nearest place value.

Since we need to determine which place value to round to, the context suggests we should round to the nearest million for simplicity and clarity. The number \( 7,803,100 \) is closer to \( 8,000,000 \) than it is to \( 7,000,000 \).

Once rounded, we represent \( 8,000,000 \) as a single digit times an integer power of 10:

\[
8,000,000 = 8 \times 10^6
\]

So, the rounded number \( 7,803,100 \) expressed in scientific notation is \( 8 \times 10^6 \).

Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2 × 10 3 visits were reflected in their logbook during this two-week period, while only about 5 × 10 2 were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.

To find out how many times higher the number of library visits before examination day is compared to the average weekly visits, we can follow these steps:

1. Calculate the total visits made before examination day:
\[
\text{Total visits (2 weeks)} = 2 \times 10^3 = 2000
\]

2. Calculate the average weekly visits:
\[
\text{Average weekly visits} = 5 \times 10^2 = 500
\]

3. Now, we need to determine how many times higher the visits during the two-week period (2000 visits) are compared to the average weekly visits (500 visits):
\[
\text{Ratio} = \frac{\text{Total visits (2 weeks)}}{\text{Average weekly visits}} = \frac{2000}{500}
\]

4. Performing the division:
\[
\frac{2000}{500} = 4
\]

Thus, the number of library visits before examination day is **4 times higher** than the average weekly visits.