Question
how do i solve these two problems?
3log(base5)^(x^2+9)-6 = 0
log(base8)^(n-3) + log(base8)^n+4)= 1
can you tell me step by step as well as the answers? please and thank you
3log(base5)^(x^2+9)-6 = 0
log(base8)^(n-3) + log(base8)^n+4)= 1
can you tell me step by step as well as the answers? please and thank you
Answers
drwls
Here is how to do the first one. The second is similar. First simplify the algebra. Then write the log equation in a different form.
3 log(base5)^(x^2+9) = 6
log(base5)^(x^2+9) = 2
Which is another way of saying:
5^2 = 25 = x^2 + 9
x^2 = 16
x = + or - 4
3 log(base5)^(x^2+9) = 6
log(base5)^(x^2+9) = 2
Which is another way of saying:
5^2 = 25 = x^2 + 9
x^2 = 16
x = + or - 4
Ana
how'd you get the log(base5)^(x^2+9) = 2 ?
drwls
I divided both sides of the first equation by 3. It's a perfectly "legal" operation when dealing with algebraic equations.