To divide \(-\frac{3}{17}\) by \(-\frac{2}{3}\), you can multiply by the reciprocal of the divisor. The reciprocal of \(-\frac{2}{3}\) is \(-\frac{3}{2}\).
So, the calculation becomes:
\[ -\frac{3}{17} \div -\frac{2}{3} = -\frac{3}{17} \times -\frac{3}{2} \]
Now, multiplying the fractions:
\[ \frac{3 \times 3}{17 \times 2} = \frac{9}{34} \]
Thus, the result of dividing \(-\frac{3}{17}\) by \(-\frac{2}{3}\) is
\[ \frac{9}{34} \]
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