LaShawn won 71 tokens playing basketball at the county fair. At school, she gave 3 tokens to every student in her math class. She only has 5 tokens remaining. (1 point)

LaShawn started with 71 tokens and gave 3 tokens to each student in her math class. After giving away some tokens, she has 5 tokens remaining.

We can set up the equation as follows:

1. Let \( s \) be the number of students in her math class.
2. She gave away \( 3s \) tokens (3 tokens for each student).
3. Therefore, the equation can be structured as:

\[ 71 - 3s = 5 \]

Now, we can solve for \( s \):

1. Subtract 5 from both sides:

\[ 71 - 5 = 3s \]

\[ 66 = 3s \]

2. Next, divide both sides by 3:

\[ s = \frac{66}{3} \]

\[ s = 22 \]

So, the total number of students in LaShawn's math class is:

**22 students**.

thats wrong

Let’s go through the problem step-by-step to ensure everything is clear.

LaShawn starts with 71 tokens, gives 3 tokens to each student in her math class, and has 5 tokens left.

To find out how many students \( s \) she has in her class, we can set up the following equation:

1. The total number of tokens she starts with is 71.
2. She gives away \( 3s \) tokens, where \( s \) is the number of students.
3. After giving away tokens, she has 5 tokens left.

Putting it together, we can write the equation:

\[
71 - 3s = 5
\]

Now, let's solve for \( s \):

1. First, subtract 5 from both sides:

\[
71 - 5 = 3s
\]

\[
66 = 3s
\]

2. Next, divide both sides by 3:

\[
s = \frac{66}{3}
\]

\[
s = 22
\]

So, the total number of students in LaShawn's math class is indeed **22 students**.

If you believe there's an error, could you specify what part seems incorrect?

the equation is with adding not substracting

Apologies for any confusion earlier! Let’s re-evaluate the situation using addition.

LaShawn starts with 71 tokens, gives away tokens to her math class, and then has 5 tokens remaining.

Given this information, we can reframe the scenario:

1. The number of tokens she started with: 71
2. The number of tokens she has left: 5
3. The number of tokens given away is \( 3s \), where \( s \) is the number of students.

After giving away tokens, we can express the situation using an equation in terms of addition:

LaShawn starts with the number of tokens she originally had and adds the tokens remaining after giving some away:

\[
3s + 5 = 71
\]

Now, let's solve for \( s \):

1. Subtract 5 from both sides of the equation:

\[
3s = 71 - 5
\]

\[
3s = 66
\]

2. Now, divide both sides by 3:

\[
s = \frac{66}{3}
\]

\[
s = 22
\]

So, confirming once again, the total number of students in LaShawn's math class is:

**22 students**.

Thank you for your patience, and I hope this clarification helps!