Question

9 x (-33)^0 + 3/2(8 - 27^0) apply the zero power rule to create an equivalent expression

Answer 1

whats an equivalent expression to this question?

Answer 2

To simplify the expression \( 9 \times (-33)^0 + \frac{3}{2}(8 - 27^0) \) using the zero power rule, we need to remember that any non-zero number raised to the power of 0 is equal to 1.

1. Simplifying \((-33)^0\):
\[
(-33)^0 = 1
\]

2. Simplifying \(27^0\):
\[
27^0 = 1
\]

Now we can substitute these results back into the original expression:

\[
9 \times 1 + \frac{3}{2}(8 - 1)
\]

This simplifies to:

\[
9 + \frac{3}{2}(7)
\]

Now, calculate \(\frac{3}{2}(7)\):

\[
\frac{3}{2}(7) = \frac{21}{2}
\]

The expression now is:

\[
9 + \frac{21}{2}
\]

To add these, convert 9 to a fraction with a denominator of 2:

\[
9 = \frac{18}{2}
\]

So now we can add the two fractions:

\[
\frac{18}{2} + \frac{21}{2} = \frac{39}{2}
\]

Thus, the simplified equivalent expression is:

\[
\frac{39}{2}
\]

Answer 3

To create an equivalent expression to the original expression \(9 \times (-33)^0 + \frac{3}{2}(8 - 27^0)\) using the zero power rule, let's reiterate the simplification step but present it more clearly.

1. **Applying the zero power rule:**
- \((-33)^0 = 1\)
- \(27^0 = 1\)

2. **Rewrite the expression:**
\[
9 \times (-33)^0 + \frac{3}{2}(8 - 27^0) = 9 \times 1 + \frac{3}{2}(8 - 1)
\]

3. **Simplifying further:**
- This simplifies to:
\[
9 + \frac{3}{2}(7)
\]

4. **Calculating \(\frac{3}{2}(7)\):**
\[
\frac{3 \times 7}{2} = \frac{21}{2}
\]

5. **Adding the results:**
- Convert 9 to a fraction:
\[
9 = \frac{18}{2}
\]
- Now add:
\[
\frac{18}{2} + \frac{21}{2} = \frac{39}{2}
\]

### Equivalent Expression:

Thus, an equivalent expression to the original problem is:

\[
\frac{39}{2}
\]

This expression is fully simplified and equivalent to the original expression you provided.