Question

Write 0.4x + 0.2y = 0.6
in slope-intercept form. Solve for y.

Answer 1

To write the equation \( 0.4x + 0.2y = 0.6 \) in slope-intercept form (which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept), we need to solve for \( y \).

Starting with the original equation:

\[
0.4x + 0.2y = 0.6
\]

First, we want to isolate \( y \). We can do this by subtracting \( 0.4x \) from both sides:

\[
0.2y = 0.6 - 0.4x
\]

Next, to solve for \( y \), divide every term by \( 0.2 \):

\[
y = \frac{0.6}{0.2} - \frac{0.4x}{0.2}
\]

Calculating \( \frac{0.6}{0.2} \) gives us \( 3 \), and \( \frac{0.4}{0.2} \) gives us \( 2 \):

\[
y = 3 - 2x
\]

Rearranging this gives us the slope-intercept form:

\[
y = -2x + 3
\]

So, the equation in slope-intercept form is:

\[
y = -2x + 3
\]