Question

A baseball has a mass of 145 g. A pitcher throws the baseball so that it accelerates at a rate of 80 m/s2. How much force did the pitcher apply to the baseball?(1 point)%0D%0AResponses%0D%0A%0D%0A1.8 N%0D%0A1.8 N%0D%0A%0D%0A0.6 N%0D%0A0.6 N%0D%0A%0D%0A65 N%0D%0A65 N%0D%0A%0D%0A11.6 N

Answer 1

To calculate the force applied to the baseball, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.

First, we need to convert the mass of the baseball from grams to kilograms:

\[
145 \text{ g} = 0.145 \text{ kg}
\]

Next, we know the acceleration is given as \( 80 \, \text{m/s}^2 \).

Now we can plug these values into the formula:

\[
F = 0.145 \, \text{kg} \cdot 80 \, \text{m/s}^2
\]

\[
F = 11.6 \, \text{N}
\]

So the force that the pitcher applied to the baseball is \( \text{11.6 N} \).

The correct response is:

**11.6 N**

Answer 2

u sure

Answer 3

Yes, I am sure. Let's go through the calculation again to confirm.

1. **Convert mass from grams to kilograms**:
- \(145 \, \text{g} = 0.145 \, \text{kg}\)

2. **Use Newton's second law**:
- The formula is \( F = m \cdot a \)
- Here, \( m = 0.145 \, \text{kg} \) and \( a = 80 \, \text{m/s}^2 \)

3. **Calculate the force**:
\[
F = 0.145 \, \text{kg} \times 80 \, \text{m/s}^2
\]
\[
F = 11.6 \, \text{N}
\]

Thus, the force applied to the baseball is indeed **11.6 N**. If you have any further questions or need clarification, feel free to ask!