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Original Question
LaShawn won 71 tokens playing basketball at the county fair. At school, she gave 3 tokens to every student in her math class. S...Question
LaShawn won 71 tokens playing basketball at the county fair. At school, she gave 3 tokens to every student in her math class. She only has 5 tokens remaining.(1 point)
Write an equation that can be used to find the total number of students, s, in her math class.
Write an equation that can be used to find the total number of students, s, in her math class.
Answers
Answer
thats not it. we want something more like _s + _ =_
Answer
how many students are there?
Answered by
GPT-4o mini
To find the total number of students \( s \) in LaShawn's math class, you can start by setting up an equation based on the information given.
LaShawn initially had 71 tokens and after giving away tokens to her classmates, she has 5 tokens remaining. The number of tokens given away can be represented as \( 3s \) (since she gives 3 tokens to each of her \( s \) students).
You can express this situation with the following equation:
\[
71 - 3s = 5
\]
This equation can be used to find the total number of students \( s \) in her math class.
LaShawn initially had 71 tokens and after giving away tokens to her classmates, she has 5 tokens remaining. The number of tokens given away can be represented as \( 3s \) (since she gives 3 tokens to each of her \( s \) students).
You can express this situation with the following equation:
\[
71 - 3s = 5
\]
This equation can be used to find the total number of students \( s \) in her math class.
Answered by
GPT-4o mini
Sure! We can rearrange the equation to fit the format you provided.
Starting from the original equation:
\[
71 - 3s = 5
\]
We want to rearrange it into the format \( as + b = c \).
1. First, add \( 3s \) to both sides:
\[
71 = 3s + 5
\]
2. Next, subtract 5 from both sides:
\[
71 - 5 = 3s
\]
3. This simplifies to:
\[
66 = 3s
\]
Now, the equation is in the form \( as + b = c \):
\[
3s + 5 = 71
\]
Here \( a = 3 \), \( b = 5 \), and \( c = 71 \). So the final equation is:
\[
3s + 5 = 71
\]
Starting from the original equation:
\[
71 - 3s = 5
\]
We want to rearrange it into the format \( as + b = c \).
1. First, add \( 3s \) to both sides:
\[
71 = 3s + 5
\]
2. Next, subtract 5 from both sides:
\[
71 - 5 = 3s
\]
3. This simplifies to:
\[
66 = 3s
\]
Now, the equation is in the form \( as + b = c \):
\[
3s + 5 = 71
\]
Here \( a = 3 \), \( b = 5 \), and \( c = 71 \). So the final equation is:
\[
3s + 5 = 71
\]
Answered by
GPT-4o mini
To find the number of students \( s \), we can use the equation we derived:
\[
3s + 5 = 71
\]
Now, let's solve for \( s \):
1. Subtract 5 from both sides:
\[
3s = 71 - 5
\]
\[
3s = 66
\]
2. Now, divide both sides by 3:
\[
s = \frac{66}{3}
\]
\[
s = 22
\]
So, there are **22 students** in LaShawn's math class.
\[
3s + 5 = 71
\]
Now, let's solve for \( s \):
1. Subtract 5 from both sides:
\[
3s = 71 - 5
\]
\[
3s = 66
\]
2. Now, divide both sides by 3:
\[
s = \frac{66}{3}
\]
\[
s = 22
\]
So, there are **22 students** in LaShawn's math class.
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