Question

Use the Product Rule of Exponents to simplify 5 to the power of 10 times 5 to the power of 5
(1 point)
Responses

2515
25 superscript 15 baseline

550
5 superscript 50 baseline

515
5 superscript 15 baseline

2550

Answers

Answer
Find the numerical equivalent of 9to the power of9⋅9to the power of −6
. Your answer should be written without exponents. (1 point)

Answer
What is the missing exponent in the following equation?
h the power of 450 divided by h? = h215
(1 point)
Answer
Simplify 12 to the power of 87÷12 to the power of 25
.
Answer
Apply the Zero Power Rule to create an equivalent expression to 9⋅(−33)0+32(8−270)
.(2 points)
Answer
Apply the Property of Negative Integer Exponents to solve 7to the power of−3
. The answer should not contain any exponent expression or decimals.(1 point)
Answered by GPT-4o mini
To simplify \( 5^{10} \times 5^{5} \) using the Product Rule of Exponents, you add the exponents:

\[
5^{10} \times 5^{5} = 5^{10+5} = 5^{15}
\]

So, the correct answer is:

**5 superscript 15 baseline**.
Answered by GPT-4o mini
To find the numerical equivalent of \( 9^9 \cdot 9^{-6} \), we can use the Product Rule of Exponents, which states that when multiplying two powers with the same base, we add the exponents:

\[
9^9 \cdot 9^{-6} = 9^{9 + (-6)} = 9^{3}
\]

Now we can calculate \( 9^3 \):

\[
9^3 = 9 \cdot 9 \cdot 9 = 81 \cdot 9 = 729
\]

Thus, the numerical equivalent is **729**.
Answered by GPT-4o mini
To find the missing exponent in the equation

\[
\frac{h^{450}}{h^{?}} = h^{215},
\]

we can use the Quotient Rule of Exponents, which states that when dividing two powers with the same base, we subtract the exponents:

\[
\frac{h^{450}}{h^{?}} = h^{450 - ?}.
\]

We want this to equal \(h^{215}\):

\[
h^{450 - ?} = h^{215}.
\]

Setting the exponents equal to each other gives us:

\[
450 - ? = 215.
\]

Now, we can solve for the missing exponent:

\[
? = 450 - 215 = 235.
\]

Thus, the missing exponent is **235**.
Answered by GPT-4o mini
To simplify \( \frac{12^{87}}{12^{25}} \), you can use the Quotient Rule of Exponents. This rule states that when dividing two powers with the same base, you subtract the exponents:

\[
\frac{a^m}{a^n} = a^{m - n}.
\]

Applying it here:

\[
\frac{12^{87}}{12^{25}} = 12^{87 - 25} = 12^{62}.
\]

So, the simplified form is **12 to the power of 62**.
Answered by GPT-4o mini
To apply the Zero Power Rule, we need to recognize that any non-zero number raised to the power of zero equals 1. Thus, the term \((-33)^0\) can be simplified:

\[
(-33)^0 = 1.
\]

Now, substituting this back into the expression:

\[
9 \cdot (−33)^0 + 32(8 - 270).
\]

This simplifies to:

\[
9 \cdot 1 + 32(8 - 270).
\]

Now simplifying further:

\[
9 + 32(8 - 270).
\]

Next, simplify the expression inside the parentheses:

\[
8 - 270 = -262.
\]

Now substituting this back into the expression gives:

\[
9 + 32 \cdot (-262).
\]

Calculating \(32 \cdot (-262)\):

\[
32 \cdot (-262) = -8384.
\]

Now substituting this back gives:

\[
9 - 8384.
\]

Finally, calculating \(9 - 8384\):

\[
9 - 8384 = -8375.
\]

Thus, the equivalent expression is \(-8375\).
Answered by GPT-4o mini
To apply the Property of Negative Integer Exponents, we use the rule that states:

\[
a^{-n} = \frac{1}{a^n}.
\]

For \(7^{-3}\), we can rewrite it as:

\[
7^{-3} = \frac{1}{7^3}.
\]

Next, we need to calculate \(7^3\):

\[
7^3 = 7 \times 7 \times 7 = 49 \times 7 = 343.
\]

Thus,

\[
7^{-3} = \frac{1}{7^3} = \frac{1}{343}.
\]

So, the final answer is:

\[
\frac{1}{343}.
\]

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