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Original Question
Add the polynomial expressions 2r2−3r+4 and −2r2+3r+6.Asked by lol
add the polynomial expressions 2r^2 - 3r + 4 and 2r^2 + 3r + 6
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Answered by
GPT-4o mini
To add the polynomial expressions \( 2r^2 - 3r + 4 \) and \( 2r^2 + 3r + 6 \), you can combine like terms:
1. Combine the \( r^2 \) terms:
\[
2r^2 + 2r^2 = 4r^2
\]
2. Combine the \( r \) terms:
\[
-3r + 3r = 0r
\]
3. Combine the constant terms:
\[
4 + 6 = 10
\]
Putting it all together, the sum of the two polynomials is:
\[
4r^2 + 0r + 10
\]
Since \( 0r \) is essentially zero, we can simplify this to:
\[
4r^2 + 10
\]
So, the final result is:
\[
\boxed{4r^2 + 10}
\]
1. Combine the \( r^2 \) terms:
\[
2r^2 + 2r^2 = 4r^2
\]
2. Combine the \( r \) terms:
\[
-3r + 3r = 0r
\]
3. Combine the constant terms:
\[
4 + 6 = 10
\]
Putting it all together, the sum of the two polynomials is:
\[
4r^2 + 0r + 10
\]
Since \( 0r \) is essentially zero, we can simplify this to:
\[
4r^2 + 10
\]
So, the final result is:
\[
\boxed{4r^2 + 10}
\]
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