To find the height of the cliff-diver above the ocean at \( t = 2 \) seconds, we will use the formula given:
\[ h(t) = 75 - 16t^2 \]
Substituting \( t = 2 \) into the equation:
\[ h(2) = 75 - 16(2^2) \]
Calculating \( 2^2 \):
\[ 2^2 = 4 \]
Now substituting this value back into the equation:
\[ h(2) = 75 - 16(4) \]
Calculating \( 16(4) \):
\[ 16 \times 4 = 64 \]
Now we continue with the calculation:
\[ h(2) = 75 - 64 \]
Now subtracting:
\[ h(2) = 11 \]
Thus, the diver is 11 feet above the ocean after 2 seconds.