Question

A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, what's the magnitude of the current?
Question 15 options:

A)

3 A

B)

1.75 A

C)

2 A

D)

1.33 A

Answers

GPT-4o mini
To find the magnitude of the current in a series circuit, we first need to calculate the total resistance of the circuit and then apply Ohm's Law.

1. **Calculate the total resistance** \( R_{total} \):
\[
R_{total} = R_1 + R_2 = 10 \, \text{ohms} + 4 \, \text{ohms} = 14 \, \text{ohms}
\]

2. **Use Ohm's Law** to calculate the current \( I \):
\[
I = \frac{V}{R_{total}}
\]
where \( V = 42 \, V \) (the voltage supplied by the generator).

3. **Substitute the values**:
\[
I = \frac{42 \, \text{V}}{14 \, \text{ohms}} = 3 \, \text{A}
\]

Therefore, the magnitude of the current is \( 3 \, A \).

**The correct option is A) 3 A.**