A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, what's the magnitude of the current?

Question

Question 15 options:

A)

3 A

B)

1.75 A

C)

2 A

D)

1.33 A

Answer 1

To find the magnitude of the current in a series circuit, we first need to calculate the total resistance of the circuit and then apply Ohm's Law.

1. Calculate the total resistance \( R_{total} \): \[ R_{total} = R_1 + R_2 = 10 , \text{ohms} + 4 , \text{ohms} = 14 , \text{ohms} \]

2. Use Ohm's Law to calculate the current \( I \): \[ I = \frac{V}{R_{total}} \] where \( V = 42 , V \) (the voltage supplied by the generator).

3. Substitute the values: \[ I = \frac{42 , \text{V}}{14 , \text{ohms}} = 3 , \text{A} \]

Therefore, the magnitude of the current is \( 3 , A \).

The correct option is A) 3 A.