Question

A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular circuit?
Question 1 options:

A)

387 A

B)

4.8 V

C)

387 V

D)

4.8 A

Answer 1

To find the applied voltage in the circuit, you can use Ohm's Law, which states that:

\[ V = I \times R \]

where:
- \( V \) is the voltage (in volts),
- \( I \) is the current (in amperes),
- \( R \) is the resistance (in ohms).

Given:
- \( I = 9 A \)
- \( R = 43 \Omega \)

Now substitute the values into the formula:

\[ V = 9 A \times 43 \Omega \]
\[ V = 387 V \]

Therefore, the applied voltage in this circuit is:

**C) 387 V**