Question
Suppose a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 22 N?
Question 16 options:
A)
330 J
B)
352J
C)
220 J
D)
200 J
Question 16 options:
A)
330 J
B)
352J
C)
220 J
D)
200 J
Answers
GPT-4o mini
To calculate the work done when pulling a block, you can use the formula:
\[ \text{Work} (W) = \text{Force} (F) \times \text{Distance} (d) \times \cos(\theta) \]
Where:
- \( W \) is the work done (in joules, J),
- \( F \) is the applied force (in newtons, N),
- \( d \) is the distance moved (in meters, m),
- \( \theta \) is the angle between the force and the direction of motion.
Assuming that the force is applied in the same direction as the motion (which means \( \theta = 0^\circ\) and \( \cos(0) = 1 \)), the equation simplifies to:
\[ W = F \times d \]
Given:
- \( F = 22 \, \text{N} \)
- \( d = 16 \, \text{m} \)
Now, plug in the values:
\[ W = 22 \, \text{N} \times 16 \, \text{m} \]
\[ W = 352 \, \text{J} \]
So, the amount of work done is \( 352 \, \text{J} \).
The correct answer is **B) 352 J**.
\[ \text{Work} (W) = \text{Force} (F) \times \text{Distance} (d) \times \cos(\theta) \]
Where:
- \( W \) is the work done (in joules, J),
- \( F \) is the applied force (in newtons, N),
- \( d \) is the distance moved (in meters, m),
- \( \theta \) is the angle between the force and the direction of motion.
Assuming that the force is applied in the same direction as the motion (which means \( \theta = 0^\circ\) and \( \cos(0) = 1 \)), the equation simplifies to:
\[ W = F \times d \]
Given:
- \( F = 22 \, \text{N} \)
- \( d = 16 \, \text{m} \)
Now, plug in the values:
\[ W = 22 \, \text{N} \times 16 \, \text{m} \]
\[ W = 352 \, \text{J} \]
So, the amount of work done is \( 352 \, \text{J} \).
The correct answer is **B) 352 J**.