Question

The question is: A 30g sample of metal with a specific heat of .34J/g is heated to 50C. 4.8KJ of energy was transferred. What is the initial temperature?
I used:
heat=(mass)(specific heat)(change in temp)
So I did 4800J=(30)(.34)(50-x)
4800=(10.2)(50-x)
4800=510-10.2x
4290=10.2
-420.59
This can't possibly be right. Can you tell me where I went wrong? Thanks!
bobpursley
You did the calculations correctly. I expect the writer of the problem did not think when she constructed the question.


Related Questions

a 5.00g sample of Al pellets (specific heat=0.89J/oC*g) and a 10.00g sample of Fe pellets (specific... A 47.5g sample of metal is heated to 300.0ºC and placed in a calorimeter containing 75.0g water at 2... Use the calculation of specific heat for your metal as an example and determine the effect on specif... A 1000 g sample of metal with a specific heat of 0.50 J/goC is heated to 100.0oC and then placed in...